O! cursed, cursed slave.  Whip me, ye devils,
From the possession of this heavenly sight!
Blow me about in winds! roast me in sulphur!
Wash me in steep-down gulfs of liquid fire!
O Desdemona! Desdemona! dead!

Only one more phase to go.  Your token for this one is "Armstrong".

The final hurdle contains two ciphertexts.  The longer one is
encrypted with triple-DES in electronic code book mode.  It uses a
128-bit EDE key.

The RSA public key cryptosystem has been used to encipher the
triple-DES key; this forms the shorter ciphertext.  The public
exponent is 3735928559 in decimal and the public modulus is the
following 155-digit decimal integer:

10742 78829 12665 65907 17841 12799 42116 61266 39217 94753 29458
88778 17210 35546 41509 80121 87903 38329 26235 28109 07506 72083
50494 19964 33143 42555 83344 01855 80898 94268 92463.

Your task is to decipher the longer message and so discover the final
code word.  How you do this is up to you, but it will almost certainly
be much, much easier to break the RSA ciphertext by factoring the
public modulus than by any other approach.

Good luck!

